http://i63.tinypic.com/2a6ktfr.jpg

Solve for all variables.
This is actually a Grade One Entry Level Math Question in Hong Kong.

I can't read that asian pictograph bullfluff, but the answer is 42.

Instructions are in the OP, you can't understand the Math question?

i mean, if you want to be serious about it now that im sober

A = 8
B = 6
C = 5
D = 4
E = 3
F = 2
G = 7
H = 9
P = 1

200 bill? you better get to sendin pacts!

P could only be 1, you can't get to 222 by adding 2 two-digit numbers.

yeah, that is where i started.

It also can't be 0 unless one of the other letters = another... and even though I can't read the rules, it's a pretty good guess that you can't do that. :P

You didn't show your work, also, not 'the' correct answer

lol, show my work? this isnt high school.

we all know you wernt going to FA anyone 200bill cash anyways, dont act like a girl while backing out.

I would FA you 200b in FA if you had 'the' correct answer.

Although your answer may fit into the question, it is simply not 'the' answer.

after you'e done with your schoolgirl chortle, please do show your work.

why? because you and i both know you can. don't prove me wrong, son. oh, for the love of christ, please don't let me down. eye m support u heart.

There is more than one correct answer.

A=9 B=0 C=2 D=7 E=6 F=3 G=4 F=8 P=1
A=9 B=5 C=2 D=7 E=6 F=8 G=4 F=3 P=1
A=8 B=6 C=5 D=4 E=3 F=2 G=7 H=9 P=1

Now i know why Forgotten was fluffing about not wanting to live.

My answer is correct. Just because it isnt the one you wanted, doesnt make mine any less correct. You are going to have to fluff out in another fashion, lol. Or establish better initial parameters next time.

Fail. Man up and FA.

Solve for all variables. ALL.

And there's the correct answer, unless someone can find a 4th set of answer, took me hours to solve it by hand.

ford just got nerd slapped in his face after thinking he was a nerd badass

all possible solutions isnt the same as all variables.

ALL = ALL

possible solutions = variables

If you want to settle for a second place prize, show work that results in all answers.

I am God, so I am going to say that I win.

Forgotten, I want my 200b FA

im not settling for anything because you never were going to FA in the first place.

i gave a numerical value to every variable. you didnt say anything about multiple solutions or variations. i suspect so you could fluff out if someone took the time to calculate it lol. if you want to get semantical in order to fluff out, that is your choice. it is kinda sad though. not my fault you are terrible at establishing ground rules.

Show your work.

I forgot to.

that is a you problem, not a me problem.

no, that is a me problem, not a you problem.

Just found a 4th answer.

nobody cares anymore now that we know you are full of fluff

Oooo a math problem!

Ford, how many accounts do you have?

Also, if you are really that desperate, I'll pay, on express server, PM me and we'll sync which resets you want them in.

I have a few. That isn't one.

And my landfarm doesn't need FA lol!

I solved the problem. There's a total of 3741 possibilities.

Oh, and you wanted me to show the work?

<script>
/********************************************************
******************Created by Celphi**********************
******************March 19 2016**************************
********************************************************/

var group1, group2, total;
group1 = 0;
group2 = 0;

var group3, group4, index, indx, num, number, count;
count = 0;
var s = [];
var t = [];
var u = [];
var w = [];

group3 = 0;
group4 = 0;
s = [111];

// find all numbers which give a sum of 111
// generates #s for group 3 and group 4
for (group3=0;group3<99;group3++){
	for (group4=0;group4<99;group4++){
		if (group3+group4 == s[0]){
			t.push(String(group3)+ String(group4));
		}	
	}
}

// adds 0s to single digit numbers
function addZero(num){
	if (num<10)
		num = String('0'.concat(num));
	else
		num = num;
	return num;
}


function cycle(number){
// 13-98 range for group 3 & 4
// Find all #s which subtract to give 13-98
	for (group1=0;group1<99;group1++){
		for (group2=0;group2<99;group2++){
			total = group1-group2;
			//if (total >= 13 && total <= 98){
				if (total == number){
					group1 = addZero(group1);
					group2 = addZero(group2);
				w.push(String(group1)+ String(group2));
			}
		}
	}
}

for (indx=13;indx<99;indx++){
	cycle(indx);
	
	for (index=0;index<w.length;index++){
		document.write(w[index] + t[indx-13] + ' ' + count + '<br>');
	count++;
	}
	w = [];
}


// w = group A|B|C|D
// t = group E|F|G|H

</script>

It would be 3740, but all the variables could be equal to 0., thus it's 3741.
The output I have is ABCDEFGH
So 13001398 is
A=1
B=3
C=0
D=0
E=1
F=3
G=9
H=8

13
00
----
13
98
----
111

You can run the code in your console to see all the combos. The number off to the side of the 8 digit number is a counter.

If you don't know how to work your console, then just copy paste the code into the HTML section on https://jsfiddle.net/ and hit run.

@Celphi

Each variable is a single number, you can't have A and E and P all equal to 1.

And what kind of Grade 1 student is suppose be able to program?

Shrug. IDK.

Also,.. where does it say A, E & P cannot all equal 1? It's an easy fix.

And each digit does equal 1 digit.
You have 8 variables. And my program displays 8 digits. The 9th variable is always 1 except in one instance. I could make it post A= B= C= blah blah blah,... I just made it as a 8 digit string instead to make easier to read.

ABCDEFGH

// if the 0th or 4th index = 1 then don't output it to screen
if (charAt(0) ==1 && charAt(4) == 1){
// place document.write (statementhere)
}

celphi is back fluffes

A=1
B=3
C=0
D=0
E=1
F=3
G=9
H=8

AB
-CD
--------
EF
+GH
------------
PPP

It works. 1 of 3741 possibilities.

You never said it had to be done by hand Forgotten. I hate to say it, but celphi kicked your butt.

AB
CD
-----
EF
GH
------
PPP

I can explain how to do it by hand. You basically have to treat AB|CD|EF|GH as a 2 digit number. You only separate them at the end.

P =000 works when all variables are 0.
P=111 works
P=222 cannot work because 99+99= 198 which are the max values for EF|GH

So that leaves you to solve for 111.
Now that you know the sum is 111, that now means you have to find all the solutions of EF|GH that equal 111. The range goes from 12->99. (99 is the greatest number either EF|GH can ever be, and 99+12=111).

So you get all the possibilities: (PART A)
EF+GH
12+99
13+98
14+97
ect....

Once that's complete. You then have to find solutions for each of Part A solutions:
Find every solution in which you subtract two two-digit numbers that give you 12, 13, 14, 15 ect.... (basically EF)

When you do that., you get all the solutions in which my program posts.

there have been atleast 3 different people to answer this question in different ways which are all correct under the initial parameters

forgotten just makes up new rules every time, because he is too tarded to lay out rules at the beginning.

he just found out the comical way that he isnt as clever as he was seeking to prove with this post.

Why can't CD be negative and thus giving us more choices for PPP?

@Celphi,

the original pictures has instructions, chinese reading is part of the problem, each variable is a unique number

you can have 200b too for express server, since you wrote a damn program for it.

@mrford,

you didn't show work, and i offered you the 200b FA in Express already, you declined it.

Oh. So no variable can share the same value?

you irredeemable fluffwit, lol we dont read chinese. i covered this in my first post on this thread.

additionally, since you are so adept at displaying your intelligence, how long exactly do you calculate it would take you to FA me 200 billion cash on a server that doesnt allow FA?

yah, it's in the picture of the question...

why would i put up a chinese question on AT?

because if i put up an english question it would be too easy for you mathathletes

you put the question on here because you saw it on your depressing facebook feed, with a click bait title, and had nothing better to do so you tried to solve it. you thought it was hard so you came here to humble brag.

but you didnt think your ridiculous proposal through so you have ever since been backpedaling faster than a kid on a bike with a thrown chain.

still want to know about that promise to FA 40 sets worth of stock on a server where FA is coded out of the game. but ironically we already know how bad you are at math, not to mention rules.

Oh Bonus.

Math is a farce anyway. There are ALWAYS more than one possible solution / variable for addition.

It really all depends on WHAT you are adding.